The standard form equation of a circle provides key information about the circle's center and radius.
[Diagram of circle with center (h,k), radius r, and point (x,y) on circumference]
(x - h)² + (y - k)² = r²
Sometimes you'll need to convert from general form to standard form by completing the square.
x² + y² + Dx + Ey + F = 0
1. Group x and y terms:
(x² + Dx) + (y² + Ey) = -F
2. Complete the square for x and y:
(x² + Dx + (D/2)²) + (y² + Ey + (E/2)²) = -F + (D/2)² + (E/2)²
3. Write in standard form:
(x + D/2)² + (y + E/2)² = (D² + E² - 4F)/4
Equation Form | Center | Radius |
---|---|---|
(x-2)² + (y+3)² = 16 | (2, -3) | 4 |
x² + y² = 25 | (0, 0) | 5 |
(x+1)² + y² = 9 | (-1, 0) | 3 |
What is the center and radius of the circle represented by the equation x² + y² - 6x + 4y - 3 = 0?
We need to complete the square to convert from general form to standard form.
1. Rearrange terms:
x² - 6x + y² + 4y = 3
2. Complete the square for x and y:
(x² - 6x + 9) + (y² + 4y + 4) = 3 + 9 + 4
We added (6/2)² = 9 for x and (4/2)² = 4 for y
3. Write as perfect squares:
(x - 3)² + (y + 2)² = 16
4. Identify center and radius:
The correct answer is A) Center: (3, -2); Radius: 4.
Common mistakes: