Learn how to simplify, add, subtract, multiply, and divide rational expressions - fractions with polynomials in the numerator and denominator.
Fractions where both numerator and denominator are polynomials.
Examples: (x+1)/(x-2), (3x²-5)/(2x+7), 5/(x³-1)
The denominator cannot equal zero. Always identify excluded values.
For (x+1)/(x-2), x ≠ 2
Example: Simplify (x²-9)/(x²+6x+9)
1. Factor: [(x+3)(x-3)]/[(x+3)(x+3)]
2. Cancel: (x-3)/(x+3)
3. Restrictions: x ≠ -3
Multiplication: Multiply numerators and denominators
(a/b) × (c/d) = (ac)/(bd)
Division: Multiply by the reciprocal
(a/b) ÷ (c/d) = (a/b) × (d/c) = (ad)/(bc)
Example: [(x²-4)/(x+1)] × [(x+3)/(x-2)]
= [(x+2)(x-2)(x+3)]/[(x+1)(x-2)]
= (x+2)(x+3)/(x+1), x ≠ 2, -1
Requires a common denominator:
Example: (3/x) + (2/(x+1))
1. LCD: x(x+1)
2. Rewrite: [3(x+1) + 2x]/[x(x+1)]
3. Combine: (5x+3)/[x(x+1)]
Which of the following is equivalent to [1/(x-3)] - [2/(x²-9)] for all x ≠ ±3?
Follow these steps:
Step-by-Step Solution:
1. Factor denominator: x²-9 = (x+3)(x-3)
2. LCD is (x+3)(x-3)
3. Rewrite first term: [1/(x-3)] = (x+3)/[(x+3)(x-3)]
4. Now subtract: [(x+3)-2]/[(x+3)(x-3)]
5. Simplify numerator: (x+1)/[(x+3)(x-3)] = (x+1)/(x²-9)
The correct answer is C) (x+1)/(x²-9).